write the sum of first 6 odd term
Answers
Answer:
The sum of first 6 odd term is 36
36 is Sum of first 6 odd terms
Given : First 6 odd terms
To Find : Sum
Solution:
Using a rule :
Sum of first n odd terms = n²
Hence Sum of first 6 odd terms = 6² = 36
Sum of first 6 odd terms = 36
Doing Normal Addition
first 6 odd terms are
1 , 3 , 5 , 7 , 9 , 11
1 + 3 + 5 + 7 + 9 + 11 = 36
Using AP
a = 1
d = 2
n = 6
Sₙ = (n/2)(2a + (n - 1)d)
= (6/2)(2*1 + (6 - 1) 2)
= 3(2 + 10)
= 3(12)
= 36
Sum of first 6 odd terms = 36
Arithmetic sequence
Sequence of terms in which difference between one term and the next is a constant.
This is also called Arithmetic Progression AP
Arithmetic sequence can be represented in the form :
a, a + d , a + 2d , …………………………, a + (n-1)d
a = First term
d = common difference = aₙ-aₙ₋₁
nth term = aₙ = a + (n-1)d
Sₙ = (n/2)(2a + (n - 1)d)
Sum of Arithmetic sequence (AP) is called Arithmetic series
Learn More:
Find the sum of first n odd natural numbers. - Brainly.in
brainly.in/question/899893
What is the sum of first 'n' odd positive integers? - Brainly.in
brainly.in/question/8349491