Question

Write the sum of intercepts cut off by the plane added to i + j - k - 2 equal to zero on the three axis

Answer 1

Answer:

Where a , b , c are the intercepts cut off by the plane at x , y and z respectively. Step 1: The given equation is 2 x + y − z = 5. Divide throughout by 5,we get.   $\large\frac{x}{\Large\frac{2}{5}}$$+\large\frac{y}{5}$$+\large\frac{z}{-5}$$=1$

Step 2:

Equation of a plane in intercept form is $\large\frac{x}{a}$$+\large\frac{y}{b}$$+\large\frac{z}{c}$$=1$

Where $a,b,c$ are the intercepts cut off by the plane at $x,y$ and $z$ axes respectively.

$a=\large\frac{2}{5}$$,b=5$ and $c=-5$

Thus the intercepts cutoff by the plane are $\large\frac{5}{2}$$,5$ and $-5$