Write the sum of real roots of the equation x²+ x - 6 =0
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First of all, the equation is x2 + |x| − 6 = 0
CASE 1: x>0 then |x| = x
⇒ x2 + x− 6 = 0
⇒ x2 + 3x – 2x – 6 = 0
⇒ (x + 3)(x−2) = 0
⇒ x = 2, – 3
CASE 2: x<0 |x| = – x
⇒ x2 − x − 6 = 0
⇒ x2 − 3x + 2x−6 = 0
⇒ (x − 3)(x + 2) = 0
⇒ x = −2, 3
So the sum of the roots is 2 + (– 3) + (– 2) + 3
= 0
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