Write the sum of roots of 2x^2-3x-1=0
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Answered by
1
✏ Answer
The sum of the roots is given by
-b/a = -(-3)/2
✏ 3/2
Answered by
1
Hello !!
Is very simple solve your question. See the resolution below.
The formula.
Sum = [(-b + √D)/2a] + [(-b - √D)/2A]
Find the discriminant.
D = b^2 - 4ac
D = (-3)^2 - 4(2)(-1)
D = 9 + 8
D = 17
Now, you put the information of the statement in the formula and find the sum.
Sum = [(-(-3) + √17)/2(2)] + [(-(-3) - √17)/2(2)]
Sum = [(3 + √17)/4] + [(3 - √17)/4]
Sum = [(4(3 + √17) + 4(3 - √17))/16]
Sum = [(4(3 + √17) + 4(3 - √17))/16]
Sum = 24/16
Sum = 12/8
Sum = 6/4
Sum = 3/2
Final result : the sum is 3/2.
I hope I have collaborated !
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