Write the sum of two consecutive successor and two consecutive processes of 378
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Answer:
762 is the number...
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ANSWER =9 IS THE ANSWER
Step-by-step explanation:
let the first no. be x
second no.=x + 9
third no.= x+9+9 =x+18
NOW ;
x × x+9+x +18 =378
•3x ×27= 378
•3x=378 -27
•x =351/3
*so x =117
first number :117
second number :117+9=126
third number :117+18 =135
so 117 ,126 and 135 are consecutive multiples which are divisible by 9( whose sum is 378 )
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