Question

write the three consecutive multiples of 8 . The sum of multiples is 888 . write the multiples
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Answer 1

Let the multiples be x+8, x+16 and x+24

According to Question:

x+8 + x+16 + x+24 = 888

3x + 48 = 888

3x = 888-48

3x = 840

x = 840/3

x = 280

x+8 = 280+8 → 288

x+16 = 280+16 → 296

x+24 = 280+24 → 304

Answer 2

PLEASE MARK AS BRAINLIEST.

100% CORRECT.

Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.