Math, asked by ritay7750, 9 months ago

Write the three consecutive numbers after 2998.​

Answers

Answered by pinkysinha455
3

Answer:

3X + 3 = 2998. 3X + 3 - 3 = 2998 - 3.

3X = 2995. 3X/3 = 2995/3.

X = 998 1/3. Since 998 1/3 is not an integer, there is no true answer to this problem. However, there are three numbers that add up to 2998. The first number is (998 1/3), the second number is (998 1/3) + 1, and the third number is (998 1/3) + 2.

Step-by-step explanation:

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Answered by purvirajput2004
2

Here we will use algebra to find three consecutive integers whose sum is 2998. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2998. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2998

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2998

3X + 3 = 2998

3X + 3 - 3 = 2998 - 3

3X = 2995

3X/3 = 2995/3

X = 998 1/3

Since 998 1/3 is not an integer, there is no true answer to this problem.

However, there are three numbers that add up to 2998. The first number is (998 1/3), the second number is (998 1/3) + 1, and the third number is (998 1/3) + 2. Therefore, we could make this the answer to "Three consecutive numbers that add up to 2998 are?":

998 1/3 + 999 1/3 + 1000 1/3 = 2998

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