Write the three digit numbers where hundred place is ‘a’ tenth place is 4 and unit place is b.
Answers
Answered by
2
Step-by-step explanation:
Correct option is
A
67
Let the digit in ten's place be x.
Then, the digit in the hundred's place =
3
x
and digit in the unit's place = 4×
3
x
=
3
4x
∴ The original number = 100×
3
x
+10×x+
3
4x
=
3
100x
+10x+
3
4x
=
3
100x+30x+4x
=
3
134x
In the new number,
Digit in the ten's place =
3
4x
Digit in the unit's place =x
Digit in the hundred's place =
3
x
100×
3
x
+10×
3
4x
+x=
3
100x+40x+3x
=
3
143x
Given,
3
143x
−
3
134x
=18
⇒
3
9x
=18
⇒x=6
∴ Original number =
3
134
×6=268
∴25% of 268=
100
25
×268=
4
268
=67
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