Write the trigonometric ratios of sinA ,tanA and cotA in terms of sec A
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Step-by-step explanation:
sinA=sinA/1=sinA÷cosA/(1÷cosA)=sinA/cosA/1/cosA
=tanA/secA
= √tan²A/secA
= √(sec²A-1)/secA
tanA = √tan²A = √(secA²-1)
cotA = 1/tanA = 1/√(secA²-1)
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