Question

write the two factors of the algebraic expression x²+px+q if p=a+b and q=a×b. explain steps by step​

Answer 1

Answer:

⚘Solution:

The factors of the polynomial are

$\sf{(x + a) \: \: and \: (x + b)}$

$\sf{p = a + b}$

$\sf{q = ab}$

Find factors of polynomial:

$\sf{ {x}^{2} + px + q = {x}^{2} + (a + b)x + ab = 0 }$

$\sf{ {x}^{2} + ax + bx + ab = 0}$

$\sf{(x + a)(x + b) = 0}$

Answer 2

Answer:

(x+a)(x+b)

Step-by-step explanation:

x^2+ax+bx+ab

x(x+a)+b(x+a)

(x+a)(X+b)