Question

write the unit place number which are not perfect cube.​

Answer 1

Correct answer:-

To determine the digits at unit's place of the cubes of given numbers, first we need to find their cubes.

1^3

=1, 2^3

=8, 3^3

=27, 4^3

=64, 5^3

=125, 6^3

=216, 7^3

=343, 8^3

=512, 9^3

=729, 10^3

=1000

The digits at unit's place are 1,8,7,4,5,6,3,2,9,0

Let's arrange them in order, we get 0,1,2,3,4,5,6,7,8,9 as digits at unit's place.

Each digit occurs at the end of some cube. Hence one cannot conclude that some number is not a cube by looking at the last digit.

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