Question

Write the unit vector in the direction of A = 5i + j - 2i

Answer 1

unit vector = A/|A|

here A= 5i+j-2k

so |A| = √5^2+1^2+2^2

= √25+1+4

= √30

so Acap = (5i+j-2k)/√30

Answer 2

Given :

A vector , v = 5i + j - 2i .

To Find :

The unit vector along v .

Solution :

We know , unit vector along any vector v is given by :

$\hat{v}=\dfrac{v}{|v|}$     .....( 1 )

Here ,

$|v|=\sqrt{5^2+1^2+(-2)^2}\\\\|v|=\sqrt{30}$

Putting value of v and |v| in equation 1 .

We get :

$\hat{v}=\dfrac{5i+j-2i}{\sqrt{30}}$

Hence , this is the required solution .

Learn More :

Vectors

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