Math, asked by mahaksaifi594, 4 months ago

write the vale of k for which the system oy equations 2x-y =5and 6x+ky=15 has infinitely, many solutions .​

Answers

Answered by GitaTatei
1

Ans: -3

Explanation:

The given system of equations are;

2x-y=5 which implies that 2x-y-5=0

Similarly,6x+ky=15 which implies that 6x+ky-15=0

Here, a1=2,b1= -1 and c1= -5

a2=6, b2=k and C2= -15

For infinitely many solution;

a1/a2=b1/b2=c1/c2

Implies that a1/a2=2/6 which is also equal to 1/3

b1/b2= -1/k

and c1/c2= -5/-15 which is also equal to 1/3

So,we can find that 1/3= -1/k

implies that K= -3

Therefore the value of the K is -3

(Ans.)

I hope my answer is helpful to you....

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