Chemistry, asked by bhalepandurang2039, 6 days ago

write the value of 2.303 rtin nerst equation

Answers

Answered by Jaswindar9199
0

The value of 2.303*RT/zF is 58 mV at room temperature.

  • As we know that the Nernst equation is related to the movement of a single ion lineage through selective channels, on is supposed to be related only to the concentration of that ion. So when handling K ion, one need not be concerned about Na ion.

How The value of 2.303*RT/zF is 58 mV at room temperature?

  • R = 8.135; T = 273 + 25 (room temperature of 25 oC); z = 1; F = 9.684 × 104.

2.303 \times  \frac{8.135 \times 298}{1 \times 96840}  \\  = 0.0578

  • Approve for presently that this has the units of Volts. Since this is a lesser value it is most conveniently conveyed in mV (1/1000 of a volt), in which case it comes to be 57.8 mV. For most bases like for calculations, this is rounded up to 58 mV.

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