Question

write the value of (√3+√2)(√3-√2)​

Answer 1

$= ( \sqrt{3} + \sqrt{2} )( \sqrt{3} - \sqrt{2})$

$=\sqrt{3} ( \sqrt{3} - \sqrt{2} ) \ \sqrt{2}( \sqrt{3} - \sqrt{2} )$

$= 3 - \sqrt{6} + \sqrt{6} - 2 \\ = 3 - 2 \\ = 1$

We can also see that that the question is in the the form of

$(x + y)(x - y)$

we know that ,the formula of the expression which is equal to

${x}^{2} - {y}^{2}$

Therefore,

$= ({ \sqrt{3} }^{2} - { \sqrt{2} }^{2} ) \\ = 3 - 2 \\ = 1$