Math, asked by lkvrrc, 11 months ago

write the value of 5^2+log5^7​

Answers

Answered by sachingraveiens
1

Answer:

29.8927

Step-by-step explanation:

5² + log 5⁷

⇒ 25 + 7 log 5

⇒ 25 + 7 * 0.6989 = 25 + 4.892 = 29.8927

Answered by harendrachoubay
12

The value of 5^{2} +\log 5^7 is equal to 29.8927.

Step-by-step explanation:

We have,

5^{2} +\log 5^7

To find, the value of 5^{2} +\log 5^7 = ?

∴  5^{2} +\log 5^7

= 25 + 7 \log 5

Using the logarithm identity,

\log a^m=m\log a

= 25 + 7\log 5

= 25 + 7 × 0.6989 [ ∵ \log 5 = 0.6989]

= 25 + 4.892

= 29.8927

∴ The value of 5^{2} +\log 5^7 = 29.8927

Thus, the value of 5^{2} +\log 5^7 is equal to 29.8927.

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