write the value of (5/cot^2) -(5/cos^2)
Answers
Answered by
11
Hey !!!
5/cot²¢ - 5/cos²¢
=> 5 /cos²¢/sin²¢ - 5/cos²¢
=> 5sin²¢ /cos²¢ - 5/cos²¢
=> -5(-sin²¢ + 1)/cos²¢
=> - 5(1 - sin²¢)/cos²¢
=> - 5cos²¢/cos²¢
=> - 5 Answer
**************""""""""*"
Hope it helps you !!
@Rajukumar111
5/cot²¢ - 5/cos²¢
=> 5 /cos²¢/sin²¢ - 5/cos²¢
=> 5sin²¢ /cos²¢ - 5/cos²¢
=> -5(-sin²¢ + 1)/cos²¢
=> - 5(1 - sin²¢)/cos²¢
=> - 5cos²¢/cos²¢
=> - 5 Answer
**************""""""""*"
Hope it helps you !!
@Rajukumar111
Answered by
6
✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴
Hey !!!
5/cot²¢ - 5/cos²¢
=> 5 /cos²¢/sin²¢ - 5/cos²¢
=> 5sin²¢ /cos²¢ - 5/cos²¢
=> -5(-sin²¢ + 1)/cos²¢
=> - 5(1 - sin²¢)/cos²¢
=> - 5cos²¢/cos²¢
=> - 5
✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴
Hope it helps you !!
Hey !!!
5/cot²¢ - 5/cos²¢
=> 5 /cos²¢/sin²¢ - 5/cos²¢
=> 5sin²¢ /cos²¢ - 5/cos²¢
=> -5(-sin²¢ + 1)/cos²¢
=> - 5(1 - sin²¢)/cos²¢
=> - 5cos²¢/cos²¢
=> - 5
✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴✴
Hope it helps you !!
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