Question

Write the value of 6 cotfA -

6 cosec A.​

Answer 1

Answer:

6=\cosec(A)−cot(A)=1−cos(A)sin(A)=2(sin(A2))22sin(A2)cos(A2)=tan(A2)6=\cosec(A)−cot⁡(A)=1−cos⁡(A)sin⁡(A)=2(sin⁡(A2))22sin⁡(A2)cos⁡(A2)=tan⁡(A2)

This should exclude angles AA where sin(A2)=0sin⁡(A2)=0, but those don't yield a well-defined value for the original expression (one could consider these solutions, though, of a sort).

So A=2\atan(6)A=2\atan(6), with some highly questionable other possibilities where AA is a multiple of half a right angle.