write the value of 9+9tan square A
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Answer:
The value of 9sec²A-9tan²A =9
Step-by-step explanation:
The value of 9sec²A-9tan²A
= 9(sec²A-tan²A)
/* By Trigonometric identity:
\boxed {sec^{2}A-tan^{2}A=1}
sec
2
A−tan
2
A=1
*/
= 9 ×1
= 9
Therefore,.
The value of 9sec²A-9tan²A =9
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