Question

write the value of a b c for the equation 2y =10-y2?​

Answer 1

Answer:

25

Step-by-step explanation:

2y =10-2y

then you take 2y and add the other y2 which is nothing but 2y= 4y,then

4y=10

y=4/10

=2.5 is your answer

Answer 2

Values of a,b and c are 1,2 and -10 respectively.

Given:

• $2y = 1 0- {y}^{2}$

To find:

• Write the coefficients i.e. a,b and c of equation.

Solution:

Concept to be used:

A standard quadratic equation is $\bf a {x}^{2} + bx + c = 0$ ; a≠0.

here,

a,b and c are coefficients of x²,x and constant term.

Step 1:

Write the equation in standard form.

$2y = 10 - {y}^{2}$

$\bf {y}^{2} + 2y - 10 = 0$

Step 2:

Write the coefficients.

Compare the equation ${y}^{2} + 2y - 10 = 0$ with standard equation.

We can easily say that

$\bf a = 1 \\ \bf b = 2 \\ \bf c = - 10$

Thus,

Values of a,b and c are 1,2 and -10 respectively.

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