Write the value of a50- a10 for the A.P. 1, 6, 11, 16.
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Answered by
0
a = 1
d = 5
A50 = a + 49d
= 1 + 49*5
= 1 + 245
= 246
A10 = a + 9d
= 1 + 9*5
= 1* 45
= 46
A50 - A10 = 246 - 46
= 200
d = 5
A50 = a + 49d
= 1 + 49*5
= 1 + 245
= 246
A10 = a + 9d
= 1 + 9*5
= 1* 45
= 46
A50 - A10 = 246 - 46
= 200
Answered by
0
a1 = 1
a2 = 6
d = a2-a1 = 6 -1 = 5
a50 - a10
= a + (50 - 1)d - [a + (10 - 1)d]
= 1 + 49 × 5 - [1 + 9 × 5]
= 246 - 46 = 200
a2 = 6
d = a2-a1 = 6 -1 = 5
a50 - a10
= a + (50 - 1)d - [a + (10 - 1)d]
= 1 + 49 × 5 - [1 + 9 × 5]
= 246 - 46 = 200
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