write the value of cos squared theta minus 1 by sin squared theta
Answers
Answered by
5
Answer: -1
Step-by-step explanation:
Assuming you meant the question to be as such,
(cos²ø - 1)/sin²ø
Using sin²ø + cos²ø = 1,
=> (cos²ø - 1)/sin²ø
= (-sin²ø)/sin²ø
= -1
Answered by
1
Answer:
1
Step-by-step explanation:
cos^2Ѳ-1÷sin^2Ѳ
cos^2Ѳ+sin^2Ѳ=1
∴ cos^2Ѳ-1=sin^2Ѳ
∴sin^2Ѳ/Sin^2Ѳ=1
hope this answer helps you...
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