write the value of cot2q _1/sin2q
Attachments:
Answers
Answered by
0
Answer:
cot 2 q - 1/sin 2 q ( 1 / sin 2 = cosec 2)
= cot 2 q - cosec 2 q (cot 2 - cosec 2 = 1)
= 1
Step-by-step explanation:
Plz Plz Plz Mark Me As Brainliest
Answered by
3
Here,
tan
A
+
sin
A
=
p
tan
A
−
sin
A
=
q
L
.
H
.
S
=
p
2
−
q
2
=
(
tan
A
+
sin
A
)
2
−
(
tan
A
−
sin
A
)
2
=
(
tan
A
+
sin
A
+
tan
A
−
sin
A
)
(
tan
A
+
sin
A
−
tan
A
+
sin
A
)
=
(
Here,
tan
A
+
sin
A
=
p
tan
A
−
sin
A
=
q
L
.
H
.
S
=
p
2
−
q
2
=
(
tan
A
+
sin
A
)
2
−
(
tan
A
−
sin
A
)
2
=
(
tan
A
+
sin
A
+
tan
A
−
sin
A
)
(
tan
A
+
sin
A
−
tan
A
+
sin
A
)
=
(
2
tan
A
)
⋅
(
2
sin
A
)
=
4
tan
A
sin
A
=
4
√
tan
2
A
sin
2
A
=
4
√
(
sec
2
A
−
1
)
sin
A
[
A
s
sec
2
θ
−
tan
2
θ
=
1
]
=
4
√
sec
2
A
.
sin
2
A
−
sin
2
A
=
4
√
sin
2
A
cos
2
A
−
sin
2
A
=
4
√
tan
2
A
−
sin
2
A
=
4
√
(
tan
A
+
sin
A
)
(
tan
A
−
sin
A
)
=
4
√
p
q
[
A
s
.
tan
A
+
sin
A
=
p
and
tan
A
−
sin
A
=
q
]
=
R
.
H
.
S
Similar questions