Question

write the value of following
(3i+2j)(6i-2k)
please give me full explain​

Answer 1

Answer:

the identity we can use here is (a+b)(c-d)

Explanation:

Here a = 3i, b= 2j, c= 6i d= -2k

(a+b)(c+d) = (ac+bc)+(-ad-bd)

So, (3i+2j)(6i-2k) = (27i²+12ij) + ( -6ik - 4jk )

There are no like terms, so there is no simplification. hence your answer is ,

27i²+12ij-6ik-4jk