Math, asked by abcd546852, 2 months ago

write the value of identity (x-y)³​

Answers

Answered by prakash1951
0

( x - y )³ = x³ - y³ - 3xy ( x - y )

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Answered by swapnamatoor
2

Answer:

x−y)

3

=> (x-y)(x-y)(x-y)(x−y)(x−y)(x−y)

=> (x^2 + y^2 -2xy)(x-y)(x

2

+y

2

−2xy)(x−y)

=> x^3 - x^2y + xy^2 - y^3 - 2x^2y + 2xy^2x

3

−x

2

y+xy

2

−y

3

−2x

2

y+2xy

2

=> x^3 - y^3 -3x^2y + 3xy^2x

3

−y

3

−3x

2

y+3xy

2

=> < em > < strong > x^3 - y^3 - 3xy (x-y) < /strong > < /em ><em><strong>x

3

−y

3

−3xy(x−y)</strong></em>

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