Math, asked by sapnaramaiya3112, 1 year ago

Write the value of k for which the following pair of linear equations has no solution :- 4x+y=11;kx+3y=5

Answers

Answered by kunaljangra53219
0

Answer:wisis

Step-by-step explanation:

Answered by aayushkhanna1
1

Answer: k = 12

Step-by-step explanation:

a₁ = 4, a₂ = k, b₁ = 1, b₂ = 3, c₁ = 11, c₂ = 5

For no solution,

a₁/a₂ = b₁/b₂ ≠ c₁/c₂

4/k = 1/3 ≠ 11/5

4/k = 1/3

By doing its reciprocal,

k/4 = 3

k = 12

4/k ≠ 11/5

By doing its reciprocal,

k/4 ≠ 5/11

k ≠ 20/11

Therefore, the value of k = 12

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