Question

Write the value of k for which the following pair of the linear equation has a unique solution:-
x+ky+6=0 ; 2x+3y+8=0

Answer 1

Answer:

$k = \dfrac{3}{2}$

Step-by-step explanation:

Given

Equations are,

x+ky+6 = 0 ......(1)

2x+3y+8 = 0 ........(2)

has a unique solution

To Find

value of K

Solution

Since, eq. (1) and (2) has uniqur solution

Therefore,

$\dfrac{a_{1}}{a_{2}} = \dfrac{b_{1}}{b_{2}}$

we have,

a1 = 1 ; b1 = k

a2 = 2 ; b2 = 3

Putting the values

$\dfrac{1}{2} = \dfrac{k}{3}$

$k = \dfrac{3}{2}$

Answer 2

Answer:

$\huge\underline\mathfrak\blue{Solution}$