Question

write the value of k for which the system of equations 3x + ky + 14 = 0, 2x - y = 0 has a unique solution

Answer 1

Answer: Any value except -3/2

Step-by-step explanation:

For equations a1x + b1y + c1=0 and a2x + b2y + c2=0 to have a unique solution

this condition must be followed-

                    a1/a2 ≠ b1/b2

3x+ky+14=0     and 2x-y=0

a1=3                            b1=k

a2=2                           b2=-1

3/2≠-k

k≠-3/2

Therefore value of k can be anything except -3/2.