Write the value of k for which x=2 is zero of polynomial x^2+2xk+2
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x=2
2^2+2×2k+2=0
4+4k+2=0
6+4k=0
4k=-6
k=-6/4
k=-3/2
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Answered by
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LET X= 2
NOW PUT THIS VALUE ON EQUATION AS FOLLOWS -
(2)^2+2(2)k+2= 0
4+4k+2=0
6+4k=0
4k= -6
k= -6/4
SO k= -3/2
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