Question

Write the value of n and l for its electrons in the valence shell atomic number is 29.

Answer 1

Answer:

as electronic configuration is 2 8 8 11

Explanation:

n shell =11

l shell =8

Answer 2

The n is 4 and the l is 0.

• The element with atomic number 29 is Cu or copper.
• The electronic configuration of the Cu atom is given as follows-
• ${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{1} {3d}^{10}$
• Hence its valance shell is 4s.
• Now n is called the principal quantum number and for 4s the value of n is 4.
• l is called the azimuthal quantum number and the value of l for 4s is 0.