Question

write the value of resistance of resistor having four colour bands in the order brown, red, black, and silver​

Answer 1

1st band, Brown---> 1 (ten's digit)

2nd band, Red---> 2 (ones digit)

3rd band, Black----> x1 (3rd band multiplier)

4th band, Silver----> +-10% (error)

Answer---> 12ohm +-10%

Answer 2

Answer:

12ohm with 10% tolerence

Explanation:

The Resistor color code of brown is 1

red is 2

We need to write this continuously as 12.

The resistor color code of black is 0

This should be written as 10 to the power of 0,which is equal to 1.

Multiply both of them, 12*1 = 12 ohms.

The tolerence of silver is 10%.

So conclude it as 12 Ohms 10%.