Question

Write the value of sec^2 θ (1+sinθ) (1-sinθ)

Answer 1

Hello mate

♥♦♥

Good morning

Answer 2

Answer:

1

Step-by-step explanation:

sec^2θ(1+sinθ)(1-sinθ)

(sec^2θ)(1^2)-(sin^2θ)     ... (a+b)(a-b) = (a^2)-(b^2)

(sec^2θ)(1)-(sin^2θ)

(sec^2θ)(cos^2θ)  ....(sin²θ +cos²θ = 1)

1/cos²θ (cos²θ)

1