Question

write the value of sec²A(1+sinA)(1-sinA)​

Answer 1

Answer:

Given,

sec^2 A (1 + sinA)(1 - sinA)

or, 1/cos^2 A × (1 + sinA)(1 - sinA)

(since, sec A = 1/cos A)

using identity, a^2 - b^2 = (a + b)(a - b), we get,

1^2 - sin^2 A/cos^2 A

[we know,

sin^2 A + cos^2 A = 1

so, 1 - sin^2 A = cos^2 A]

therefore,

cos^2 A/cos^2 A = 1