Math, asked by BrainlyHelper, 11 months ago

Write the value of cot^{2}\Theta-\frac{1}{sin^{2}\Theta }.

Answers

Answered by nikitasingh79
1

Answer:

The value of cot² θ - 1/sin² θ is - 1.

Step-by-step explanation:

Given : cot² θ - 1/sin² θ

= cot² θ - (1/sinθ)²

= cot² θ - cosec²θ

[By using the identity, 1/sinθ = cosecθ ]

= - 1

[By using the identity , cot² θ - cosec² θ = - 1]

cot² θ - 1/sin² θ = - 1

Hence, the value of cot² θ - 1/sin² θ is - 1.

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Answered by Anonymous
2

 cot^{2}\Theta-\frac{1}{sin^{2}\Theta } \\  \\   =  \frac{cos^{2}\Theta}{sin^{2}\Theta}  - \frac{1}{sin^{2}\Theta }  \\  \\  =  \frac{cos^{2}\Theta - 1}{sin^{2}\Theta}  \\  \\  =  \frac{-sin^{2}\Theta}{sin^{2}\Theta}  \\  \\ =  -1 \\  \\

#लवलव!

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