write the value of
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=> The given problem is to show why log x – log y = log (x/y). Since “log” without any designated base can be understood to mean a common logarithm or, in other words, a logarithm to the base 10, we’ll take care to prove the given logarithmic property: log x ‒ log y = log (x/y) for any legitimate base “a,” where a > 0 and a ≠ 1, not just for base a =10; therefore, so there’s no misunderstanding, we’ll take some license here by replacing log x with logₐ x, by replacing log y with logₐ y, and by replacing log (x/y) with logₐ (x/y).
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