Question

write the value of the k for which the quadratic equation km(m-2)+6=0 has equal roots

Answer 1

$for \: equal \: roots \: d = 0 \\ therefore \\ b^{2} - 4ac = 0 \\ km(m - 2) + 6 = 0 \\ km^{2} - 2km + 6 = 0 \\ \\ now \: b^{2} - 4ac = 0 \\ therefore \: ( - 2k)^{2} - 4(k)(6) = 0 \\ {4k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ 4k = 0 \: or \: k - 6 = 0 \\ k = 0 \: or \: k = 6$