Question

Write the value of x for which 2x, x+10 and 3x+2 are in A.P. ???

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Answer 1

Step-by-step explanation:

as we know in AP;

T2-T1=T3-T2.

So putting values;

x+10-2x=3x+2-x+10

-x+10=2x+12

-3x=2

x=-2/3

Answer 2

Answer:

$\large{\underline{\boxed{\sf x = 6}}}$

Step-by-step explanation:

Given that -

2x, x + 10, 3x + 2 are in A.P. This implies that the common difference between the second term and first term, and between third term and second term would be same.

According to the question;

(x + 10) - 2x = (3x + 2) - (x + 10)

⇒ x + 10 - 2x = 3x + 2 - x - 10

⇒ 10 - x = 2x - 8

⇒ 2x + x = 10 + 8

⇒ 3x = 18

⇒ x = $\dfrac{18}{3}$

⇒ x = 6

Hence, the value of x is 6.