Question

Write the value of x for which x+2, 2x+3 are three consecutive terms of an A.P ​

Answer 1

Write the Given,

x+2,2x,2x+3 are in A.P.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

The consecutive numbers are : 5+2,2(5),2(5)+3

⇒7,10,13

Answer 2

Answer:

ɢɪᴠᴇɴ,

x+2,2x,2x+3 ᴀʀᴇ ɪɴ ᴀ.ᴩ.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

ᴛʜᴇ ᴄᴏɴꜱᴇᴄᴜᴛɪᴠᴇ ɴᴜᴍʙᴇʀꜱ ᴀʀᴇ : 5+2,2(5),2(5)+3

⇒7,10,13