write the value of x³-y³-6xy if x-y=2
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Answer:
Given, x+y=2
Cube on both sides give,
(x+y)3=x3+y3+3xy(x+y)
(2)3=x3+y3+3xy(2) ………………because, (x+y)=2
Hence,
8=x3+y3+6xy
Step-by-step explanation:
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