write the values of cot square theta minus one upon sin squared theta
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The given equation is:
cot^2{\theta}-\frac{1}{sin^2{\theta}}
On solving this equation, we get
=\frac{cos^2{\theta}}{sin^2{\theta}}-\frac{1}{sin^2{\theta}}
=\frac{cos^2{\theta}-1}{sin^2{\theta}}
=\frac{-sin^2{\theta}}{sin^2{\theta}}
=1
Thus, the value of the given equation is 1.
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