write the values of cot square theta minus one upon sin squared theta
Answers
Answered by
2
The given equation is:
cot^2{\theta}-\frac{1}{sin^2{\theta}}
On solving this equation, we get
=\frac{cos^2{\theta}}{sin^2{\theta}}-\frac{1}{sin^2{\theta}}
=\frac{cos^2{\theta}-1}{sin^2{\theta}}
=\frac{-sin^2{\theta}}{sin^2{\theta}}
=1
Thus, the value of the given equation is 1.
Answered by
1
Answer:
hope it is helpful for u
make me brainliest
Attachments:
Similar questions
History,
5 months ago
Hindi,
5 months ago
Computer Science,
5 months ago
India Languages,
10 months ago
Physics,
1 year ago