Chemistry, asked by gg4835512, 1 year ago

write the values of the four quantum numbers for 20th electron for scandium

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Answered by Anonymous

☆ Chemistry
4s2

n = 4
l = 0
m =1
s = 1/2 , -1/2

May it help you ________# Aion-13

Answered by Afreenakbar

Answer:

The values of the four quantum numbers for the 20th electron in scandium are:

he values of the four quantum numbers for the 20th electron in scandium are:n = 4

l = 0

m = 1

s = $\frac{1}{2} , \frac{ - 1}{2}$

Explanation:

To determine the values of the four quantum numbers for the 20th electron in scandium, we need to first know the electronic configuration of scandium.

The electronic configuration of scandium is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹.

Therefore, the 20th electron in scandium will be in the 3d subshell.

The four quantum numbers that describe the state of an electron are:

Principal quantum number (n)
Azimuthal quantum number (l)
Magnetic quantum number (m)
Spin quantum number (s)

The principal quantum number (n) for the 20th electron in scandium is 3, since it is in the 3d subshell.

The azimuthal quantum number (l) can have values from 0 to n-1. For the 3d subshell, the possible values of l are 0, 1, and 2. Since the 20th electron is in the 3d subshell, the value of l is 2.

The magnetic quantum number (m) can have values from -l to +l. For the 3d subshell, the possible values of m are -2, -1, 0, +1, and +2. We do not know which specific orbital the 20th electron is in, so we cannot determine the value of m.

The spin quantum number (s) can have values of +1/2 or -1/2, depending on the direction of electron spin. We do not know the spin direction of the 20th electron, so we cannot determine the value of s.

Therefore, the values of the four quantum numbers for the 20th electron in scandium are:

the values of the four quantum numbers for the 20th electron in scandium are:n = 4

l = 0

m = 1

s = $\frac{1}{2}, \frac{ - 1}{2}$