Question

write the xpand (m+7)³?​

Answer 1

$\blue{Hence,(a+b)³=a³+3a²b+3ab²+b³} \\ \\ (m + 7)^{3} = {m}^{3} + 3m^{2} 7 + 3m7^{2} + {7}^{3} \\ \\={m}^{3} + 3m^{2} 7 + 3m49 + 343\\ \\={m}^{3} + 3×7×m^{2} + 3×49×m + 343\\ \\ = \green{ \boxed{{m}^{3 } + 21m^{2} + 147m + 343}}$