write the zero of polynomial x²-x-6
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Answered by
16
x^2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
x=3,-2
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
x=3,-2
Answered by
9
x² - x - 6 = 0
x² - (3 - 2)x - 6 = 0
x² - 3x + 2x - 6 = 0
x(x - 3) + 2(x - 3) = 0
(x + 2)(x - 3)=0
Hence, zeroes are -2 & 3
x² - (3 - 2)x - 6 = 0
x² - 3x + 2x - 6 = 0
x(x - 3) + 2(x - 3) = 0
(x + 2)(x - 3)=0
Hence, zeroes are -2 & 3
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