Question

write the zeroes of 100x square minus 81​

Answer 1

Answer:

zeroes of 100x^2-81 are:-

100x^2-81=0

100x^2=81

x^2=81/100

x=√81/100

x=plus and minus 9/10

So zeroes of x are 9/10 and -9/10

Answer 2

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