Question

Write the zeroes of√3x^2+10x+7√3

Answer 1

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Answer 2

Solution :

Let

p(x ) = √3x² + 10x + 7√3

Take p( x ) = 0

=> √3x² + 10x + 7√3 = 0

Splitting the middle term , we get

=> √3x² + 3x + 7x + 7√3 = 0

=> √3x² + (√3×√3 )x + 7x + 7√3 = 0

=> √3x( x + √3 ) + 7( x + √3 ) = 0

=> ( x + √3 )( √3x + 7 ) = 0

=> x + √3 = 0 or √3x + 7 = 0

=> x = -√3 or x = -7/√3

Therefore ,

-√3 , -7/√3 are zeroes of p(x).

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