Question

Write the zeroes of the polynomial x*2-x-6

Answer 1

The answer is here in the attached pic

Answer 2

${x}^{2} - x - 6 \\ {x}^{2} + 2 x - 3x - 6 \\ x(x + 2) - 3(x + 2) \\ x - 3 = 0 \: \: \: \: \: \: x + 2 = 0 \\ x = 3 \: \: \: \: \: x = - 2 \\ verification \\ p( x) = {x}^{2} - x - 6 \\ p(3) = {3}^{2} - 3 - 6 \\p(3) = 9 - 3 - 6 \\ p(3) = 0 \\ \\ p( - 2) = { - 2}^{2} - ( - 2) - 6 \\ p( - 2) = 4 + 2 - 6 \\ p( - 2) = 6 - 6 \\ p( - 2) = 0 \\ \\ 3 \: and - 2 \: are \: the \: zeroes \: of \: the \: polynomial \: p(x) = {x}^{2} - x - 6$