Write the zeroes of the polynomial x2–x – 4
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p(x) => x² - x - 4 = 0
x² - 2x + 2x - 4 = 0 (By splitting the middle term)
x(x - 2) + 2(x - 2) = 0
(x+2) (x-2) = 0
Hence, x+2 = 0
x = -2
And, x - 2 = 0
x = 2
So -2 and 2 are the zeros of the given polynomial p(x)
x² - 2x + 2x - 4 = 0 (By splitting the middle term)
x(x - 2) + 2(x - 2) = 0
(x+2) (x-2) = 0
Hence, x+2 = 0
x = -2
And, x - 2 = 0
x = 2
So -2 and 2 are the zeros of the given polynomial p(x)
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=>x^2 -2x+2x-4=0
=>x(x-2)+2(x-2)=0
=>(x+2)(x-2)=0
=>x=2 or -2
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