Write the zeros of 4x square - 7
Answers
Answered by
10
Hi,
Here is your answer !
_____________________________
Given Equation : 4x² - 7
To find zero we need to put
4x² - 7 = 0
=> 4x² = 7
=> x² = 7/4
=> x = √(7/4)
=> x = ± √7 / 2
Hence,
Zeros of 4x² - 7 are √7/2 and -√7/2
Here is your answer !
_____________________________
Given Equation : 4x² - 7
To find zero we need to put
4x² - 7 = 0
=> 4x² = 7
=> x² = 7/4
=> x = √(7/4)
=> x = ± √7 / 2
Hence,
Zeros of 4x² - 7 are √7/2 and -√7/2
Answered by
5
Hey!
4x² - 7 = 0
( 2x )² - ( √7 )² = 0
[ Identity :- a² - b² = ( a - b ) ( a + b ) ]
( 2x - √7 ) ( 2x + √7 ) = 0
=> ( 2x - √7 ) = 0
x = √7 /2
=> ( 2x + √7 ) = 0
x = ( -√7 / 2 )
So, the zeros are :- √7/2 and -√7/2
4x² - 7 = 0
( 2x )² - ( √7 )² = 0
[ Identity :- a² - b² = ( a - b ) ( a + b ) ]
( 2x - √7 ) ( 2x + √7 ) = 0
=> ( 2x - √7 ) = 0
x = √7 /2
=> ( 2x + √7 ) = 0
x = ( -√7 / 2 )
So, the zeros are :- √7/2 and -√7/2
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