Question

write the zeros of polynomial x2-x-4​

Answer 1

Answer:

-2 and 2 are the zeros of the given polynomial.

Explanation:

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Answer 2

$\color{red}\huge{\underline{\underline{\bf GIVEN\dag}}}$

• ${x}^{2} - x - 4 = 0$

$\color{red}\huge{\underline{\underline{\bf SOLUTION\dag}}}$

$\bf Using\:Quadratic\:formula$

$\blue{\boxed{\bf x=\frac{-b±\sqrt{b^{2}-4ac}}{2a}}}$

$x = \frac{ - ( -1 )± \sqrt{ {( - 1)}^{2} - 4(1)( - 4) } }{2(1)}$

$x = \frac{1± \sqrt{1 + 16} }{2}$

$x = \frac{1± \sqrt{ 17} }{2}$

$\orange{\boxed{\therefore x = \frac{1 + \sqrt{ 17} }{2}} }$

$\bf \: \: \: \: \: \: \: \: \: \: (or)$

$\orange{\boxed{ \therefore x = \frac{1 - \sqrt{ 17} }{2} }}$

HOPE THAT HELPS!!