write the zeros of the polynomial of x square - 2 x minus 3
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Answer:
Step-by-step explanation:
x² - 2x - 3 = 0
=> x² - 3x + x - 3 = 0
=> x(x - 3) + 1(x - 3) = 0
=> (x + 1)(x - 3) = 0
=> x = - 1 or 3
Zeroes of polynomial x² - 2x - 3 are half f of the zeros of polynomial ax² + bx + c
Zeroes of ax² + bx + c are -2 & 6
hence polynomial would be
(x -(-2))(x - 6)
= (x + 2)(x - 6)
= x² - 4x - 12
comparing with
ax² + bx + c
a = 1
b = -4
c = -12
a - b - c
= 1 -(-4) -(-12)
= 1 + 4 + 12
= 17
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Answer:
heyy mate. here is ur answer..
EXPLANATION:
x²-2x-3
solution:
p(x)=x²-2x-3
x²-2x-3=0
x²-2x=0+3
x²-2x=3
x²=3+2x
x²=5x
x=√5x
i hope it will help you!
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